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Keo5

aka Tiger

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  • I live in America (Muh•reh•cuh)
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  • Keo5

    3 Mathematical Conundrums

    December 24, 2011 by Keo5

    I stubled across 3 false proofs, see if you can find the errors.


    • X=Y
    • X^2=X*Y
    • X^2-Y^2=X*Y-Y^2
    • (X+Y)*(X-Y)=Y*(X-Y)
    • X+Y=Y
    • 2Y=Y
    • 2=1

    • X=0.99999...
    • 10X=9.99999...
    • 10X-X=9.99999...-X
    • 9X=9
    • X=1
    • 0.99999...=1

    This one is a word problem. Imagine a square with sides of 4, and therefore a perimiter of 16. Cut corners, and the perimiter stays the same. See below for a visual.


    • HHHHHHHHHH
    • HHHHHHHHHH
    • HHHHHHHHHH
    • HHHHHHHHHH
    • HHHHHHHHHH
    • HHHHHHHHHH


    The perimeter of the above shape is equal to the perimeter of the shape below. (_ equals negative space)

    • ____HHHH____
    • ____HHHH____
    • HHHHHHHHHH
    • HHHHHHHHHH
    • ____HHHH____
    • ____HHHH____

    Repeat to infinity. Square becomes a circle

    • 16=Pi*(2)^2

    Therefore, Pi equals 4


    That's all folks!

    ~₮iger~ :. Talk & Profile .:





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